Question

completing the squre mehtod xsqure+8x-48=0

Answer 1

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Here is the solution:

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x² + 8x - 48 = 0

Add 40 to both sides:

x² + 8x = 48

Add (b/2)² to both sides:

x² + 8x + 4² = 48 + 4²

a² + 2ab + b² = (a + b)²:

(x + 4)² = 48 + 16

Add the right hand side:

(x + 4)² = 64

Square root both sides:

x+ 4 = ±√64

Evaluate right hand side:

x+ 4 = ±8

Subtract 4 from both sides:

x = 8 - 4 or x = -8 - 4

Evaluate right hand side:

x = 4 or x = -12

Answer: x = 4 or x = -12

Answer 2

Hey !!! ^_^

Here is your answer

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${x}^{2} - 8x - 48 = 0 \\ \\ {x}^{2} - 8x + {(4)}^{2} = 48 + {(4)}^{2} \\ \\ u \: can \: see \: that \: lhs \: is \: in \: the \: form \: of \: {a + b}^{2} \\ \\ {(x - 4)}^{2} = 64 \\ {(x - 4)}^{2} - 64 = 0$
(X + 4) = ±√64

X + 4 = ±8

so ..

X = -12 or x = 4

I HOPE IT WILL HELP YOU

Thank you

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