Question

completion of square method 2x^2 + 4x -
8​

Answer 1

❣️$\textbf{\large{\pink{\underline{\underline{Step by step Explanation:-}}}}}$

$\mathrm{2x^{2}+4x-8=0}$

$\mathrm{\implies{2x^{2}+4x=8}}$

$\mathrm{\implies{2x^{2}+2\times{2x}\times{1}+1^{2}=8+1^{2}}}$

[On adding $\mathrm{(1^{2})}$ in both sides..]

$\mathrm{\implies{(2x+1)^{2}=8+1}}$

$\mathrm{\implies{(2x+1)^{2}=9}}$

$\mathrm{\implies{2x+1=\pm\sqrt{9}}}$

$\mathrm{\implies{x=\frac{-1\pm 3}{2}}}$

$\mathrm{x=\frac{-1+3}{2}}$

$\mathrm{\implies{x=\frac{2}{2}}}$

$\mathrm{\implies{x=1}}$

$\textit{\underline{and,,}}$

$\mathrm{x=\frac{-1-3}{2}}$

$\mathrm{\implies{x=\frac{-4}{2}}}$

$\mathrm{\implies{x=-2}}$

$\textit{\underline{Hence,,}}$

$\textit{The value of x is,,}$

$\mathrm{\boxed{\red{\implies{x=1}}}}$

$\mathrm{\boxed{\red{\implies{Or,,x=-2}}}}$

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