Question

complex number

find Z^-1, if Z =(2+3i) (1-i)​

Answer 1

Step-by-step explanation:

z=

(1−i)(2+3i)

1

⇒z=

5+i

1

⇒z=

5+i

1

×

5−i

5−i

⇒z=

5

2

−i

2

5−i

⇒z=

26

5

−

26

i

Therefore,

∣z∣=

(

26

5

)

2

+(

26

−1

)

2

⇒∣z∣=

(26)

2

25+1

⇒∣z∣=

26

1