Question

complex numbers
find a and b if​

Answer 1

Answer:

a=3/13 and b=2/13

Step-by-step explanation:

1/(a+ib)

a-ib/(a+ib)(a-ib)

a-ib/a²+b² = 3-2i

now compare real part and imaginary part

a/a²+b² = 3.....1

b/a²+b² = 2.....2

a/3=b/2=a²+b²

a=3b/2.....3

plug eq3 in eq1

3b/2((9b²/4)+b²)=3

b=2((9b²+4b²)/4)

b= 13b²/2

b=2/13

plug b in eq3

a=3/13

hope it helps u

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