Question

Composite Mathe
athematics - VI
eter and Area
Mr. Ve
to fence it wid
Given : Length
Barbed wire
ma has an orchard of length and by
e it with 4 rounds of barbed wire. E
· Length of the orchard = 280 m, Bread
arbed wire required for 1 round of fencing = Per
h 280 m and 200 m respectively.
d the cost of fencing at 35 per me
readth of the orchard = 200 m.
ing = Perimeter of the orchard
= 2 (length + breadth) = 2 (280 m+
= 2 x 480 m = 960 m
[ 4 rounds of fencing = 4 x 960 m = 3840 m
I ength of barbed wire required for 4 rounds of te
Cost of fencing at 35 per metre =3 (3840 x 35)
Metre =* (3840 x 35) =
1,34,400.
EXERCISE 15 (A)
ind the breadth of the rectangle whose
Cerimeter is 160 cm and whose length is:
cm = 460 cm.)
25 cm
(a) 25 cm
(b) 60 cm
(0) 56.5 cm
? | Perimeter = 160 cm
?
perimeter 200 cm.
dth), we have
25 cm
Find the length of the rectangle if the perimeter
and width are:
(a) Perimeter = 86 cm, width = 18 cm
(b) Perimeter = 128 cm, width= 25 cm
for Perimeter = 151 cm, width = 29.5 cm
Arectangular field is 72 m by 5€
round it at the rate of 3 km per
will he take in taking 2 rounds
7. A rectangular garden is 120
many rounds of this garden
be covers 2200 metres ?
8. A lid of rectangular box of s
is sealed all around with ta
an overlapping of 5 cm of
length of the tape used ?
Multiple Choice Questi
9 Find the length of a w
7 = 30 cm.
1. ob
mouired to frame a pair​

Answer 1

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