Question

composition composition of a sample of wurtzite is Fe.*.0.93...O ;1.0.what percentage of iron present in the form of Fe??​

Answer 1

Answer:

Fe;0.93 O;1.0(sample) is non-stoichiometric mixture of Fe²+ and Fe³+ ions..

let atoms of Fe³+ions are present in the means that :xFe³+: ions have been replaced by Fe²+ions....

Explanation:

Now.

number of Fe²+ ions = 0.93 - x

for electrical neutrality...

positive charge on the compound = negative charge on the compound....

so that......

2 (0.93 - x) + 3x = 2

1.86 + x = 2

x. = 0.14

%age of Fe³+ ions present

= 0.14/0.93 X 100

= 15.0 5%

Answer 2

Answer:

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.However, here number of Fe2+ present = 0.93

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.However, here number of Fe2+ present = 0.93Or No. of Fe2+ ions missing = 0.07

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.However, here number of Fe2+ present = 0.93Or No. of Fe2+ ions missing = 0.07Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07 * 2 = 0.14

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.However, here number of Fe2+ present = 0.93Or No. of Fe2+ ions missing = 0.07Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07 * 2 = 0.14To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe3+ ions. Now since, replacement of one Fe2+ ion by one Fe3+ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe3+ ions.

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.However, here number of Fe2+ present = 0.93Or No. of Fe2+ ions missing = 0.07Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07 * 2 = 0.14To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe3+ ions. Now since, replacement of one Fe2+ ion by one Fe3+ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe3+ ions.In short, 0.93 Fe2+ ions have 0.14 Fe3+ ions

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.However, here number of Fe2+ present = 0.93Or No. of Fe2+ ions missing = 0.07Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07 * 2 = 0.14To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe3+ ions. Now since, replacement of one Fe2+ ion by one Fe3+ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe3+ ions.In short, 0.93 Fe2+ ions have 0.14 Fe3+ ions100 Fe2+ ions have = 0.14/0.93 * 100 = 15.05%