composition of sample wurstite is Fe0.93 O 1.00 .. wat %age of iron is present in the form of Fe (III)?
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Fe(0.93)O(1.00)
So assume there are 93 Fe and 100 O
Now 100 O requires 200 electrons
Now assume Fe[II] are x so Fe[III] are 93-x so
2x + 3(93-x) = 200
2x + 279 - 3x = 200
279 - x =200
x = 79
So 93 - x = 93 - 79 = 14
Thus there will be 0.14 Fe[III] and 0.79 Fe[II] in Fe0.93O1.00
So assume there are 93 Fe and 100 O
Now 100 O requires 200 electrons
Now assume Fe[II] are x so Fe[III] are 93-x so
2x + 3(93-x) = 200
2x + 279 - 3x = 200
279 - x =200
x = 79
So 93 - x = 93 - 79 = 14
Thus there will be 0.14 Fe[III] and 0.79 Fe[II] in Fe0.93O1.00
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