Question

Compound A, C₈H₁₀O, is found to react withNaOI (produced by reacting Y with NaOH) andyields a yellow precipitate with characteristic smell.
A and Y are respectively

Answer 1

Answer:

Explanation:As we learnt that

Haloform reaction -

CH_{3}COR\:\:is\:oxidised\:by\:\:NaOI\:\:to\:form\:iodoform\:and\:\:RCO_{2}Na

- wherein

C_{2}H_{5}COCH_{3}+NaOH+I_{2}\rightarrow C_{2}H_{5}CO_{2}Na+CHI_{3}

 

 

 

Option 1)

This is correct.

Option 2)

This is incorrect.

Option 3)

This is incorrect.

Option 4)

This is incorrect.

Answer 2

Haloform Reaction:

In this type of reactions of methyl ketone in presence of sodium hydroxide and iodine results in formation of an carboxylate ion and iodoform.

In Option 1):

• The en-ol compound would undergo tautomerization to form a methyl ketone.

• This methyl ketone will react with sodium hydroxide and iodine resulting in formation of compound with carboxylic group and iodoform.

$\boxed{\sf{C_{8}H_{10}O \:\:\overset{(NaOH+I_{2})}{\longrightarrow} \:\:CHI_{3}(\downarrow)+ C_{6}H_{5}CO{O}^{-}{Na}^{+}}}$

Important things to note:

• The catalyst can also be used as NaOI instead of (NaOH + I2)

• After reaction , the yellow precipitate is that of Iodoform (CHI3)

So final answer :

Option 1)