Question

Compound 'A' of molecular formula C₄H₁₀O on treatment with Lucas reagent at room temperature gives compound ‘B’. When compound ‘B’ is heated with alcoholic KOH, it gives isobutene. Compound ‘A’ and ‘B’ are respectively
(a) 2-methyl-2-propanol and 2-methyl-2-chloropropane
(b) 2-methyl-1 -propanol and 1-chloro-2-methylpropane
(c) 2-methyl-1 -propanol and 2-methyl-2-chloropropane
(d) butan-2-ol and 2-chlorobutane

Answer 1

so generalising it can we say that acetone which also has has two methyl groups is non oxidisable and cannot respond to iodoform because oxidising it would mean we gotta break c-c bond??? but this is wrong!!! ( and i think after haloform we get sodium salt of acid +haloform rather than ketone!!!! )

I HOPE IT HELPS U