Compound A on reacting with baking soda produces a colourless gas C, which when passed through lime water forms a solution D. On further passing the gas C through D, another solution E is formed. Identify the nature of A and the colour of the solution E.
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A is acidic.
C is Carbon Dioxide.
D is Calcium Carbonate.
E is Calcium Hydrogen Carbonate.
See the reaction of CO2 with lime water here,
Carbon dioxide passed into limewater gives a milky solution. This is due to the insoluble suspension of calcium carbonate formed:
Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O(l)
If excess CO2 is added, the following reaction takes place:
CaCO3(s) + H2O(l) + CO2(g) → Ca(HCO3)2(aq)
The milkiness disappears since calcium bicarbonate is water-soluble.
So colour of solution of E is colourless.
Thanks.
Tripathy.
C is Carbon Dioxide.
D is Calcium Carbonate.
E is Calcium Hydrogen Carbonate.
See the reaction of CO2 with lime water here,
Carbon dioxide passed into limewater gives a milky solution. This is due to the insoluble suspension of calcium carbonate formed:
Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O(l)
If excess CO2 is added, the following reaction takes place:
CaCO3(s) + H2O(l) + CO2(g) → Ca(HCO3)2(aq)
The milkiness disappears since calcium bicarbonate is water-soluble.
So colour of solution of E is colourless.
Thanks.
Tripathy.
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