Question

Compound ‘A’ reacts with alcoholic KOH to yield compound ‘B’ which on ozonolysis followed

by reaction with Zn/H2O gives methanol and propanal. Compound ‘A’ is

a) 1-propanol b) 1-butanol c) 1-chlorobutane d) 1-chloropentane​

Answer 1

Explanation:

Given -

• Compound A reacts with Alcoholic KOH to yield Compound B.
• Compound B on Ozonolysis gives Methanal and Propanal

To Find -

• What's Compound A ?

Solution -

Compound A must be Haloalkanes because after treating Haloalkanes with Alcoholic KOH it gives Alkene.

So, It's cleared that Option A and B IS NOT Correct.

Now,

Let's Check both the remaining option -

Option C -

CH3-CH₂-CH₂-CH₂-Cl + KOH (alc.) → CH3-CH₂-CH=CH₂ + KCl + H₂O

Hence,

Compound B is Butene.

Now,

Ozonolysis of Compound B (i.e, Butene) gives

CH3-CH₂-CH=CH₂ → CH₂O + CH3-CH₂-CHO

Hence,

Ozonolysis of Butene gives Methanal and propanal.

And In question it's given that Ozonolysis of Butene gives Propanal and Methanal.

Therefore,

Option C is correct.

Answer 2

Question :

Compound ‘A’ reacts with alcoholic KOH to yield compound ‘B’ which on ozonolysis followed by reaction with Zn/H2O gives methanol and propanal. Compound ‘A’ is

a) 1-propanol b) 1-butanol c) 1-chlorobutane d) 1-chloropentane

Answer :

c ) 1 - chlorobutane.

Given :

• Compound ‘A’ reacts with alcoholic KOH.

• To yield compound ‘B’ which on ozonolysis.

Explanation :

1 - chlorobutane gives butane - 1 on reaction with alc. KOH ( dehydrohalogenetion ) which on ozonolysis yield mathanal and propanal.

For the reaction :

Refer the attachment ⬆️

Hence,

The answer is Option C - ( 1 - chlorobutane )

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