Question

COMPOUND INTEREST / 26 POINT
CLASS IX. QUESTION 13 IN THE PIC...

Answer 1

heya !!

here's your answer:

(i) Rate of depreciation = (720 - 648/720)*(100) = (72/720)*100 = 10%

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(ii) Let the original cost be x. 


Rate of depreciation 10%


Then, x - (10x/100) = 720


=>(100x - 10x)/100 = 720


=>90x/100 = 720


=>x = 720 * 10/9 = Rs 800

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(iii) Value at the end of third year = 648 - (10* 648/100) = 648 - 64.8 = Rs 583.2


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hope helped!!☺☺

Answer 2

heya !!

here's your answer:

(i) Rate of depreciation = (720 - 648/720)*(100) = (72/720)*100 = 10%

__________________________

(ii) Let the original cost be x.  

Rate of depreciation 10%

Then, x - (10x/100) = 720

=>(100x - 10x)/100 = 720

=>90x/100 = 720

=>x = 720 * 10/9 = Rs 800

__________________________

(iii) Value at the end of third year = 648 - (10* 648/100) = 648 - 64.8 = Rs 583.2