Question

compound interest and simple interest.
Find the compound interest on Rs 24,000 for
1%2 years at the rate of 10 % per annum
compounded half-yearly.​

Answer 1

Answer:

C.I =3783

Step-by-step explanation:

p= 24000rs

N=3 because due to semi annually 3×1/2 months are there

R= 10% but 1/2 years r= 10/2=5%

Amount =p (1+r/100)^n

=24000(1+0.05)^3

24000×1.05×1.05×1.05

Amount = 27783

C.I =27783 -24000

CI =3783