Question

Compound interest on a certain sum of money
at 5% per annum for two years is * 246.
Calculate simple interest on the same sum for
3 years at 6% per annum.​

Answer 1

Answer:

Let the sum=P Rs.

S.I=50 Rs.

Rate of interest=5 %

Time =2 years.

S.I=

100

P×R×T

50=

100

P×5×5

P=

5×2

50×100

=500Rs.

C.I. of 500 Rs

Amount=500(1+

100

5

)

2

⇒500×

100

105

×

100

105

⇒500×

20

21

×

20

21

⇒551.25

C.I=551−500−51.25Rs.

Answer 2

Given :-

• $\sf Compound \: Interest(C.I) = 246 \: rupees$

• $\sf Time(t) = 2 \: years$

• $\sf Rate\% = 5\%$

To Find :-

• $\sf Simple \: Interest(S.I) = ?$

Solution :-

$\small\underline{\pmb{\sf \:According \: to \: the \: question :-}}$

$\qquad\leadsto\quad \sf \green{C.I= A - p }$

$\qquad\leadsto\quad \sf 246 = A - p$

$\qquad\leadsto\quad\sf A = 246 + p$

$\qquad\leadsto\quad\sf A= p(1 + \frac{r}{100} )^{t}$

$\qquad\leadsto\quad\sf 246 + p = p \times (1 + \frac{5}{100} )^{2}$

$\qquad\leadsto\quad\sf 246 + p = p \times (1 + 0.05)^{2}$

$\qquad\leadsto\quad\sf \sf 246 + p = p \times 1.1025$

$\qquad\leadsto\quad\sf\sf 246 = 1.1025p - p$

$\qquad\leadsto\quad\sf 246 = 0.1025p$

$\qquad\leadsto\quad\sf p = \frac{246}{0.1025}$

$\green{ \qquad\leadsto\quad \sf p = 2400 \: rupees}$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

$\qquad$ ☀️$\sf Principal = 2400 \: rupees$

$\qquad$ ☀️$\sf Rate\% = 6\%$

$\qquad$ ☀️$\sf Time = 3 \: years$

$\small\underline{\pmb{\sf \:Putting \: the \: values :-}}$

$\qquad\leadsto\quad\sf \pink{S.I= \frac{p \times r \times t}{100}}$

$\qquad\leadsto\quad\sf S.I= \frac{2400 \times 6 \times 3}{100}$

$\qquad\leadsto\quad\sf S.I = 24 \times 6 \times 3$

$\qquad\leadsto\quad\sf \pink{\sf S.I = 432 \: rupees}$

$\therefore\:\underline{\textsf{Simple interest is \textbf{ 432 \: rupees}}}.$