Question

compound interest on a certain sum of money at 5% per annum for 2 years is rupees 246 calculate simple interest on the same sum for 3 years at 6% per annum​

Answer 1

Answer:

₹240

Step-by-step explanation:

Let the sum be x

Then, amount on x =

$x + (1 + {\frac{5}{100}})^{2} \\ x + ( { \frac{20 + 1}{20} })^{2} \\ x + \frac{21}{20} \times \frac{21}{20} = \frac{441x}{400}$

Therefore, C.I. =

$\frac{441x}{400} - x = \frac{441x - 400x}{400} = \frac{41x}{400}$

But A/Q, C.I. = ₹246

Therefore, the sum =

$\frac{41x}{400} = 246 \\ 41x = 246 \times 400 \\ x = \frac{246 \times 400}{41} = 2400$

Now the S.I. on the sum =

$₹( \frac{2400 \times 5 \times 2}{100} ) =₹240$

Answer 2

Question ;

Compound interest on a certain sum of money at 5% per annum for 2 years is rupees 246 .

Calculate simple interest on the same sum for 3 years at 6% per annum.

Answer :

Simple interest on the same sum for 3 years at 6% per annum is Rs.432.

Given :

Compound interest (C.I) = Rs.246

Rate of interest for C.I (R1) = 5%p.a

No.of years (n) = 2 years

Time for Simple Interest (T) = 3years

Rate of interest for S.I (R2) = 6%p.a

To find :

The simple Interest (S.I)

Solution :

We know that,

We know that,Amount = (1 + r/100)^n

We know that,Amount = (1 + r/100)^nC.I = Amount (A) - Principal(P)

=> 246 = P(1 + 5/100)^2 - P

=> 246 = P{(100 + 5)/100}^2 - P

=> 246 = P( 105/100)^2 - P

=> 246 = P(21/20)^2 - P

=> 246 = P {( 21/20^2) - 1}

=> 246 = 41/400 × P

=> P = 246 × 400/41

=> P = 2400

We also know,

S.I = PRT/100

=> S.I = (2400 × 6 × 3)/100

=> S.I = 24×6×3

=> S.I = 432

Hence, simple interest on the same sum for 3 years at 6% per annum is Rs.432.

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