Math, asked by max09, 24 days ago

Compound interest on Rs. 10,000 invested for 1 year and 3 months at 8% per annum compounded
annually is

Answers

Answered by pritambansod21
3

Step-by-step explanation:

Given,

Given,Principal (P) = 10,000

Rate (R)=8\% Per annum compounded half Yearly

=

 \frac{8}{2}\% \: per \: half \: year \:

=4% Per Half year

Time (N) = 1Year =2 half years. (As 1 year=2 half rears)

Amount (A) =

p(  {1 +  \frac{r}{100} })^{n}

=

10000(1 +  \frac{4}{100} )^{2}

=

10000 ({ \frac{100 + 4}{100} })^{2}

=

10000( { \frac{104}{100} })^{2}

=

10000 \:  \times  \:  \frac{104 \times 104}{100 \times 100}

=

10000 \:  \times  \:  \frac{10816}{10000}

= 10816

Therefore,Amount = Rs 10,816

Now,

Amount = Principal + Interest

10816 = 10000 + Interest

10816 - 10000 = Interest

816 = lnterest

therefore,interest = 816

Thus,

Thus,Amount =Rs 10,816

& Compound interest=Rs816

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