Math, asked by raoaqsa70, 9 days ago

Compound interest on Rs=5000 for 6 1/2 years at 2 2/2 % compounded semi - annually​

Answers

Answered by ShreyanshuGulkari
2

Answer:

Solution

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It is given that 

Principal (P) = 5000

Rate of interest (r) = 6% p.a.

Period (n) = 2 years 

We Know that 

Amount = P(1+r/100)n

Substituting the values 

=5000(1+6/100)2

By further calculation 

= 5000×53/50×53/50

= 5618

Here 

CI = A - P

Substituting the values 

=5618−5000

= 618

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Answered by VishalRai46
2

Amount = 6,067.76

I (interest) = 1,067.76

Step-by-step explanation:

Principal Amount = 5000

Rate of intrest = 2+(2/2) = 3%

Time = 6+(1/2) = 13/2 = 6.5

First, convert R as a percent to r as a decimal

r = R/100

r = 3/100

r = 0.03 rate per year,

Then solve the equation for A

A = P(1 + r/n)^nt

A = 5,000.00(1 + 0.03/2)^(2)×(6.5)

A = 5,000.00×(1 + 0.015)^(13)

A = 6,067.76

A = 6,067.76

A = P + I where

P (principal) = 5,000.00

I (interest) = 1,067.76

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