Question

Compound interest on rupees 8000 for 1 years at 10% per annum compounded half yearly is

Answer 1

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P = Rs 8000
R = 10% p.a = 10/2% half yearly = 5%
T = 1 years = n = 2 for half yearly
As we know that
A = P (1+R/100)^n
$= 8000 \times (1 + \frac{5}{100}) {}^{2} \\ = 8000 \times ( \frac{21}{20} ) {}^{2} \\ = \frac{8000 \times 21 \times 21}{20 \times 20} \\ = 8820$
Now CI = A - P
$= 8820 - 8000 \\ = 820$
So The compound interest is Rs 820

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Answer 2

Answer:

Rs. 820

Step-by-step explanation:

P = Rs. 8000

R = 10% p.a; half yearly = 5%

T = 1 years; 2 for half yearly

Compound Interest Formula

A = P (1+R/100)^T

$A = 8000 * (\frac{210}{200} )^2\\\\= 8000 * \frac{210}{200} * \frac{210}{200}\\\\= 2 * 21 * 210\\\\= 8820$

Now, CI = A - P

$CI = 8820 - 8000\\= 820$

So The Compound Interest is Rs. 820.

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