Question

compound interest p=1000 at10% A for 1 year​

Answer 1

Answer:

$Compound \: \: Interest, A = P( 1 + \frac{r}{n} ) {}^{n}$

Given,P = 1000 , r = 10 , n = 1

$Therefore, A = 1 000(1 + \frac{10}{1} ) {}^{1}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1000(1 + 10)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1000(11)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: = 11000$

Thus , The compound interest = Rs.11000