compound intrest on rs 90000 is 14976 of two years then find rate of interest
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C.I.=P[(1+R/100)^n-1]
14976/90000+1=(1+r/100)^2
14976+90000/90000=(1+r/100)^2
104976/90000=(1+r/100)^2
(324/300)^2=(1+r/100)^2
2400/300=r
r=8%
14976/90000+1=(1+r/100)^2
14976+90000/90000=(1+r/100)^2
104976/90000=(1+r/100)^2
(324/300)^2=(1+r/100)^2
2400/300=r
r=8%
vivek242:
second step after the formula didnot understand
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