Question

compound when treated with zinc in methanol, an alkene is formed which on ozonolysis gives acetaldehyde as a major product briefly explain reaction give name and structure of compound?​

Answer 1

Answer:

sorry I didn't understand your question

Answer 2

Dihaloalkane will transform into two moles of acetaldehyde.

Explanation

1) When dihaloalkane on reacting with zinc in presence of methanol it will lead to the formation of an alkene. Here1,2-dihalobutane reacts with zinc in presence of methanol to form 2-butene.

2) 2-Butene on ozonolysis leads to the formation of two moles of acetaldehyde.

$CH_{3} CH(X)CH(X)CH_{3}$ + Zn (methanol)→$CH_{3} CHCHCH_{3}$

$CH_{3}CHCHCH_{3}$ +$O_{3}$→ $2 CH_{3} CHO$

Final answer

The name of the compound is dihaloalkane here halo group will be either bromine or chlorine