Question

compound with emperical formula AB has vapour density 3 times its empirical formula
weight

Answer 1

Answer:

      Molecular Formula ⇒ A₆B₆

Explanation:

Molecular Formula = {Empirical formula}ₙ

n = Molecular Mass / Empirical Mass = MM / EM

n = MM / EM ----{i}

Vapor density = Molecular mass / 2

Molecular mass = 2.Vapor density ----{ii}

From question - Vapor density = 3 × Empirical Mass ----{iii}

from {ii} and {iii}

Molecular mass = 2 × 3 × Empirical Mass

Molecular mass = 6 × Empirical Mass

6 = Molecular mass / Empirical Mass ----{iv}

from {i} and {iv}

n = 6

Molecular Formula - {Empirical formula}ₙ

                                = {AB}ₙ

                                = {AB}₆

Molecular Formula = A₆B₆