compound with empirical formula C3H7,the weight in its half mole is 0.043×103.what will be its molecular formula.
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Answer:
C6H14
Explanation:
Empirical formula is given C3H7
Empirical formula weight is equal to 43
1/2 mole weighs 43 g
1 mole weighs 86 g
we know that mass of 1 mole of a compound is its molecular weight.
so molecular weight of compound is 86
we know;
n= molecular weight/ empirical formula weight
so n = 86/43
n = 2
so molecular formula is 2(C3H7)
which is C6H14.
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