Question

compounded annually.
7. Find the amount and the compound interest on
compounded annually.
15625 for 3 years at 12% per annum.
Dind the difforonan boton tho gimolo intenant au L
.​

Answer 1

Answer:

Step-by-step explanation:

Given :-

Principal = 5,000

Rate = 9%

Time = 2 years

To Find :-

Difference between the simple interest and compound interest.

Formula to be used :-

= P (R/100)ⁿ

Solution :-

Putting all the values, we get

= P (R/100)ⁿ

= 5000 (9/100)²

= 5000 × 81/10000

= 405,000/10000

= 40.5

Hence, The difference between the simple interest and compound interest is 40.5.

Answer 2

Answer:

$\large{\underline{\boxed{\mathfrak\green{Difference \: b/w \: SI \: and \: CI = Rs. 40.5}}}}$

Given:-

• Principal (p) = Rs.5000
• Rate of interest (r) = 9%
• Time(n) = 2 years.

To find:-

• Difference between Simple interest and Compound interest = ?

$\rm At \: first, \\\\\rm We \: know, \\\\\dag\: {\boxed{\rm{Simple \: interest = P \times r \times n }}}$

$\dashrightarrow\sf SI = 5000 \times 9\% \times 2 \\\\\dashrightarrow\sf SI = 5000 \times \dfrac{9}{100}\times 2 \\\\\dashrightarrow\sf SI = \sf\green{Rs.900}$

$\rule{100}{2}$

$\rm Again,we \: know, \\\\\dag \: {\boxed{\rm{CI = P(1 + r)^n - P }}}$

$\dashrightarrow\sf CI = 5000(1 + 0.09)^2 - 5000 \\\\\dashrightarrow\sf CI = 5000(1.09)^2 - 5000 \\\\\dashrightarrow\sf CI = 5000 \times 1.1881 - 5000 \\\\\dashrightarrow\sf CI = 5940.5 - 5000 \\\\\dashrightarrow\sf CI = \sf\blue{Rs.940.5}$

$\rule{200}{1}$

$\star{\underline{\sf{Difference \: \: b/w \: \: SI \: \: and \: \: CI \: \: :- }}}$

$\dashrightarrow\sf Difference = CI - SI \\\\\dashrightarrow\sf Difference = Rs.(940.5 - 900) \\\\\dashrightarrow\sf Difference = \large{\boxed{\sf\blue{Rs.40.5 }}}$

${\underline{\therefore{\text{Difference \: between \: CI \: \& \: SI = Rs.40.5 }}}}$