Chemistry, asked by kavithasushanth10, 5 months ago

compressibility factor (z) of he(g) at low pressure and at 273 k is

Answers

Answered by AnirbanHaldar

0

Answer:

as the pressure is very low. so it is negligible.

now,z=V/RT=46.2/(o.o82*273)=2.o6 atm mol inverse

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