Chemistry, asked by aayu120503, 1 year ago

compressibility factor z of helium at low pressure and at 273 K is
p = pressure \\ \: a \: and \: b = vander \: wall \: constant \\ r = gas \: constant \\ {v}^{m} = most \: probable \: velocity<br /> 1) \frac{1}{2} \\ 2)1 + \frac{pb}{rt} \\ 3)1 + \frac{b}{rt} \\ 4)1 - \frac{a}{ {v}^{m} rt}

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Answered by Anonymous
11

#Answered@C29

#PlsMARK

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Answered by danger75
2

Answer:

your answer will be 1+pb/RT

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