Question

Compute 2^10 * 2^8 * 2^6 * 2^4 * 2^2 * 2^{-1} * 2^{-3} * 2^{-5} * 2^{-7} * 2^{-9}

Answer 1

Step-by-step explanation:

This is in the form of

a^m * a^n = a^(m+n)

2^(10+8+6+4+2) * 2^(-1-3-5-7-9)

2^(30) * 2^(-25)

2^(30) * 1/(2^25)

2^(30)÷2^(25) (or) 2^(30)/2^(25)

There are 30 2's in numerator and 25 2's in denominator

25 2 's are cancelled

Remaining there are 5 two's in numerator

So 2^5 is the answer

2^5= 32

32 is the answer