Math, asked by damayantibank, 4 months ago

compute
(2^-3-2^-4) (2^-3+2^-4)​

Answers

Answered by prithapaul35
0

= (2^-3-2^-4) (2^-3+2^-4)

by (a+b)(a-b) = a²-b²

= (1/8)²- (1/16)²

= 1/8×8 - 1/16×16

= 4/8×8×4 - 1/16×16

= 3/8×8×4

= 3/256

Answered by Simranjeetkaur2001
0
(2^-3-2^4)(2^-3+2^-4)
(2^-3)² - (2^4)²
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