Question

Compute 2j × (3i - 4k) + (i + 2j) × k.​

Answer 1

we have,

(In case of VECTOR)

i× i = 0, j ×j = 0, k × k = 0

i×j = k , j×k = i, k×i = j

j×i = (-k), k×j = (-i), i×k = (-j)

Given,

2j × (3i - 4k) + (i × 2j) × k

= -6k -8i + (-j) + 2i

= -6i - j - 6k

= -(6i + j + 6k) .

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