Question

compute

(56/28)^0 ➗ (2/5)^3×16/25​

Answer 1

Answer:

(56/28)^0 ÷ (2/5)³(16/25)

a^0=1

1÷2³×16

5³×25

1÷2³×2⁴

5³×5²

a^m×a^n=a^(m+n)

1÷2^(3+4)

5^(3+2)

1÷2^7

5^5

5^5

2^7

3125

128

Answer 2

The correct answer for the above equation is 10.

Given,

$(\frac{56}{28})^{\frac{0}$ ÷$(\frac{2}{5})^{\frac{3}{ }$ × $\frac{16}{25}$

To Find,

Compute the above equation.

Solution,

$(\frac{56}{28})^{\frac{0}$ ÷ $(\frac{2}{5})^{\frac{3}{ }$ × $\frac{16}{25}$

As we all anything with power 0 will be 1.

So,

1 ÷ $(\frac{2}{5})^{\frac{3}{ }$ × $\frac{16}{25}$

we will convert 16 and 25 into the power of 2 and 5 respectively.

2⁴ and 5².

= 1 ÷ $\frac{2^{3} }{5^{3} }$ ×$\frac{2^{4} }{5^{2} }$

= 1 × $\frac{5^{3} }{2^{3} }$ × $\frac{2^{4} }{5^{2} }$

= $5^{3-2}$ × $2^{4-3}$

= 5×2

=10.

The correct answer for the above equation is 10.

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