Question

compute:㏒₉27-㏒₂₇9
Kindly answer

Answer 1

Answer:

For a number to be divisible by 11, difference of the sum of its alternate digits must be divisible by 11,

The only number of the form 13q7 that are divisible by 11 is 1397 where (1+9)-(3+7) = 0 is divisible by 11

Hence, q = 9

Also as we can see from the sum above,

p + 8 = q (There is no carry as 9+4=13 in hundreds place)

=> p +8=9

p = 1

Hence p+q = 1+9 = 10