Question

compute all outer
and Inner
angles
of the
triangle​

Answer 1

let the triangle as ABC

angle BAC =77°

angle ABC =58°

by angle sum property

angleA +angleB+ angleC=180°

77°+58°+angleC=180°

135°+angleC=180°

angle C=180°-135°

angleC=45°

angle BCA=45°

Now let those outer points as D,E and F

now we have three line segments AD,BE and CF

Now by angle sum property on line segment

angle BAC + angleBAF=180°

77°+angleBAF=180°

angleBAF=180°-77°

angleBAF=103°

angleABC+angleDBC=180°

58°+angle DBC=180°

angleDBC=180°-58°

angleDBC=122°

angleBCA+angleACE=180°

45°+angleACE=180°

angleACE=180°-45°

angleACE=135°

hence computed