Math, asked by pavan8562, 1 year ago

compute co efficient of mean deviation from AM for the following series
CI =0-10 10-20 20-30 30-40 40-50
f= 6 28 51 11 4​

Answers

Answered by amitnrw
41

Answer:

0.287

Step-by-step explanation:

CI =0-10 10-20 20-30 30-40 40-50  

X      5      15      25         35       45

f=     6      28      51          11        4​

fX     30   420    1275     385     180

∑ f = 100

∑fX = 2290

Mean = ∑fX/∑ f  = 2290/100 = 22.9

|X-Mean|   17.9  7.9  2.1   12.1   22.1

f |X-Mean|  107.4  221.2  107.1  133.1   88.4

∑f |X-Mean| = 657.2

Mean deviation from Mean = ∑f |X-Mean| / ∑ f   = 657.2/100 = 6.572

Coefficient of mean deviation from Mean = 6.572/22.9 =0.287

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