Compute for the specific weight (N/m3) of a spherical ball if the diameter is 21 cm and has a mass of 10 kg.
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Answer:
Volume of one balloon :
=
3
4
πr
3
=
3
4
×
7
22
×(
2
21
)
3
=4851 cm
3
=4.851 litre
Let n balloons be filled; thus, total volume of hydrogen used in filling balloons
=4.851×n litre
Total volume of hydrogen in the cylinder at NTP,
V=
300×1
20×2.82×273
=51.324 litre
Actual volume of H
2
to be transferred to balloons
=51.324−2.82(2.82 litre retained in the cylinder)
=48.504 litre
No. of balloons filled
′
n
′
=
4.851
48.504
≈10.
Explanation:
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