compute gravitational acceleration at the surface of the planet Jupiter which has a diameter as 11 times as compared with that of the earth and a mass equal to 318 times that of earth
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Answer:
Hence, M
J
=318 M
e
;R
J
=11.2 R
e
;V
e
=11.2 km/s
We know, V
J
=
R
J
2GM
J
and V
e
=
R
e
2GM
e
∴
V
e
V
J
=
M
e
M
J
×
R
J
R
e
⇒V
J
=V
e
M
e
M
J
×
R
J
R
e
V
J
=11.2{
M
e
(318 M
e
)
×
(11.2 R
e
)
R
e
}
2
1
=11.2(
11.2
318
)
2
1
=59.7 km/s.
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