Question

Compute =iota+iota^2+iota^3+iota^4​

Answer 1

Iota can be represented as 'i'.

We know that :-

$i=\sqrt{-1}$

$i^{2} =\sqrt{-1} ^{2} =-1$

$i^{3}= {\sqrt{-1}}^3= -\sqrt{-1} =-i$

$i^{4}= {\sqrt{-1}}^4=1$

So,   $i+i^{2} +i^{3}+ i^{4} =i-1-i+1$ $=0$

So, your final answer is 0.