Question

Compute number of ions present in 5.85g of sodium chloride.

Answer 1

Answer:

5.85 g ofNaCl = 1 X 5.85/58.5 = 0.1 mole. Each molecule of NaCI contains one Na ion and one Cl ion = 2 ions. Total moles of ions in 0.1 mole of NaCI = 2 x 0.1 = 0.2 moles.