Compute number of ions present in 5.8t gm of SODIUM CHLORIDE (Nacl).
[Sodium (Na) =23, Chloride (Cl) = 35.5]
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2(Na)=23
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Answer:
fFor 1gm of NaCl- 23×35.5
for 5.8gm of NaCl-23×35.5×5.8= 4735.7
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