Compute sin 75 degree and tan 15 degree from the functions of 30 degree and 45 degree
Answers
Answered by
10
Hey!buddy your answer is here....
sin75=sin(45+30)
=sin45cos30+cos45sin30
=1/√2×√3/2+1/√2×1/2
=√3/2√2+1/2√2
sin75=(√3+1)/2√2
tan15=tan(45-30)
=(tan45-tan30)/(1+tan45tan30)
tan15=(1-1/√3)/(1+√3)
May be it's helpfull for you...
please mark me as brainliest
sin75=sin(45+30)
=sin45cos30+cos45sin30
=1/√2×√3/2+1/√2×1/2
=√3/2√2+1/2√2
sin75=(√3+1)/2√2
tan15=tan(45-30)
=(tan45-tan30)/(1+tan45tan30)
tan15=(1-1/√3)/(1+√3)
May be it's helpfull for you...
please mark me as brainliest
Similar questions