Question

compute sin53/cos37 + 2tan45 - cosec60/sec30

Answer 1

Answer:

2

Step-by-step explanation:

$Value \:of \:\frac{sin53}{cos37}+2tan45-\frac{cosec60}{sec30}\\=\frac{sin(90-37)}{cos37}+2\times 1-\frac{cosec(90-30)}{sec30}\\=\frac{cos37}{cos37}+2-\frac{sec30}{sec30}\\=1+2-1\\=2$

Therefore,

$Value \:of \:\frac{sin53}{cos37}+2tan45-\frac{cosec60}{sec30}= 2$

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Answer 2

Answer:

Step-by-step explanation:

We have,

Sin53/cos37+2tan45-cosec60/sec30

=sin(90-37)/cos37+2(1)-cosec(90-30)/sec30

(since tan45=1)

=cos37/cos37+2-sec30/sec30

=1+2-1

=2