Question

compute the area of quadrilateral ABCD

Answer 1

In this quadrilateral ABCD
right triangle DBC DB=
$\sqrt{17 \times 17 - 8 \times 8} ]{?} =15$
area of triangle DBC =
$1 \div 2 \times 15 \times 8 = 60$
square cm.
Similarly in right triangle ABD,
AB =
$\sqrt{15 \times 15 - 9 \times 9 }$
=12cm.
then area of triangle ABD =
$1 \div 2 \times 12 \times 9 = 54 \: square cm$
hence area of quad.ABCD
54+60=114square cm