compute the area of the trapezium shown in the figure
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Step-by-step explanation:
1st step
calculated( co) by phythagorus ther...
17^2=8^2+CO^2
289-64=co^2
15=co
2nd step
area of triangle=1/2×base×height
=1/2×8×15
=60
3rd step
area of rectangle=lenght×breadth
=15×6
=90
4th step
area of tarpezium= area of triangle + area of rectangle
=60+90
=150
Answered by
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Step-by-step explanation:
ok here length of OC
OC²=BC²– OB² [ pythagoras threom]
OC²=(17)² – (8)²
OC²= 289–64
OC=15 cm
Now we know area of trapezium is= 1/2×sum of parrel sides × distance between them
=1/2×(6+6+8)×15
=150 cm²
please check the answer it's correct or not
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