Compute the bulk modulus of water from the following data : Initial volume = 100.0
litres, pressure increase = 100.0 atm, final volume
100.0 atm, final volume = 100.5 litres. [Take 1 atm = 1.013
×10⁵Pa]
Answers
Answer:
Increase in volume, V=V
2
−V
1
=0.5×10
−3
m
3
Increase in pressure, p=100.0atm=100×1.013×10
5
Pa
Bulk modulus = p/(ΔV/V
1
)=pV
1
/ΔV
= 100×1.013×10
5
×100×10
−3
/(0.5×10
−3
)
= 2.026×10
9
Pa
Bulk modulus of air = 1×10
5
Pa
Bulk modulus of water / Bulk modulus of air = 2.026×10
9
/(1×10
5
)=2.026×10
4
This ratio is very high because air is much more compressible than water.
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