Question

Compute the capacity of the disk with the following parameters 512 bytes per sector, 1200
sectors per rack, 80,000 tracks per surface, 2 surfaces per platter and 7 platters per disk. Upper
Side of the top platter and lower side of the bottom platter are not used for storage.

Answer 1

Answer:

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Answer 2

Answer:

Explanation: The data in hard disk is arranged in the shown manner. The smallest division is sector. Sectors are then combined to make a track. Cylinder is formed by combining the tracks which lie on same dimension of the platters.

Read write head access the disk. Head has to reach at a particular track and then wait for the rotation of the platter so that the required sector comes under it.

Here, each platter has two surfaces, which is the r/w head can access the platter from the two sides, upper and lower.

So, will represent 400 cylinders are passed(0-399) and thus, for each cylinder 20 surfaces (10 platters * 2 surface each) and each cylinder has 63 sectors per surface.

Hence we have passed 0-399 = 400 * 20 * 63 sectors + In 400th cylinder we have passed 16 surfaces(0-15) each of which again contains 63 sectors per cylinder so 16 * 63 sectors. + Now on the 16th surface we are on 29th sector.

So, sector no = 400x20x63 + 16×63 + 29 = 505037.