Question

compute the compound interest on ₹3,200for 1 years at 8% per annum when compounded half yearly .. plss right solution not useless answer ..
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Answer 1

GIVEN :-

• Principal ( P ) = Rs. 3200.
• Time ( n ) = 1 years.
• Rate ( R ) = 8 % Per annum.

TO FIND :-

• The compound interest (CI).

SOLUTION :-

Here the rate of interest is given in per annum , so we need to convert the rate of interest in Per half yearly,

⇒ Rate ( R ) = 8 % Per annum.

⇒ Rate ( R ) = 8/2 % Per Half yearly

⇒ Rate ( R ) = 4 % Per Half yearly.

Now , As we know that the formula for amount when the compound interest is compounded half yearly,

⇒ Amount = P( 1 + R/100 )²ⁿ

⇒ Amount = 3200( 1 + 4/100)²

⇒ Amount = 3200{( 100 + 4 )/100}²

⇒ Amount = 3200( 104/100 )²

⇒ Amount = 3200( 10816/10000 )

⇒ Amount = ( 32 × 10816 )/100

⇒ Amount = 346112/100

⇒ Amount = 3461.12

Now,

⇒ compound interest = A - P

⇒ compound interest = 3461.12 - 3200

⇒ compound interest = 261.12

Hence the required compound interest is Rs. 261.12.

Answer 2

Answer:

$\huge \tt \: given$

• Principal (P) = ₹3200
• Time = 1 year = 2 half year
• Rate = 8% = 4% Half year

$\huge \tt \: to \: find$

compounded half yearly

$\huge \tt \: solution$

$\huge \bf \: a \: = {p( 1 + \frac{r}{100} )}^{n}$

$\sf \: a \: = 3200( {1 + \frac{4}{100} }^{2} )$

$\sf \: a = 3200 {(1 + \frac{104}{100} )}^{2}$

$\sf \: a = 3200 (1 + \frac {10816}{10000})$

$\sf A = \frac {(32 × 10816)}{100}$

$\sf a = \frac {346112}{100}$

$\sf \: a = 3461.12$

CI = A - P

CI = 3461.12 - 3200

CI = 261.12