compute the compound interest on rupees 4000 for 3 year at 20percent per annum
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A=p(1+r/100)^n
A=4000(1+20/100)³
A=4000(1+1/5)³
A=4000(6/5)³
A=4000×216/125
A=32×216
A=6912
CI=A-P
=6912-4000
=2912
ANOTHER METHOD
CI=P((1+r/100)^n-1)
=4000((1+20/100)³-1)
=4000((6/5)³-1)
=4000(216/125-1)
=4000((216-125)/125)
=4000×91/125
=32*91
=2912
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