Question

Compute the decrease in the blood pressure of the blood flowing through an artery the radius of which is constricted by a factor of 3. Assume that the average flow velocity in the unconstricted region is 50 cm/sec.

Answer 1

Formula used :-

A1V1 = A2V2

P1 + 1/2 S V1 ² = P2 + 1/2 S V 2²

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The blood pressure of the blood flowing through an artery the radius of which is constricted by a factor of 3.

The average flow velocity in the unconstricted region is 50 cm/sec .

So , A1 V1 = A2 V2

πr1² × V1 = π(r1/3)² × V2

V2 = 9V1

Now ,

=> P1 + 1/2 S U1² = P2 + 1/2 SV2²

=> P1 - P2 = 1/2 S ( V2² - V1² )

=> 40 s × ( 1/2)²

=> 10 s Answer

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