Question

compute the differece in masses of 1000mole each of Mg(atom) and Mg(ions)
mass of ē(9.1 * 10^-31 kg)​

Answer 1

Explanation:

Molar mass of Mg is 24 gmol-1

Thus 1000 moles of Mg would have 24000g or 24 kg.

Each Mg atom can lose 2 electrons thus the total loss per atom would be

9.1*10^-31*2.

For 1 mole, number of atomes is 6.023*10^23 atoms

For 1000 moles there are 6.023*10^26 atoms and each atom would lose 2 electrons thus the total loss would be

9.1*10^-31*2*6.023*10^26==1.096*10^-3 kg. Thus the loss in weight would be

24-0.001096=23.998904 kg