Question

Compute the following expressions for given values of the variables.
(x^2 + 3y) (3y + 7) for x = 1, y=1​

Answer 1

GIVEN VALUES :

• $: \implies \: \sf{x = 1}$
• $: \implies \: \sf{y = 1}$

GIVEN EXPRESSION :

$\longmapsto \sf{(x^2 + 3y) (3y + 7)}$

SOLUTION :

★ step 1

• simplify the given expression : (multiplication rule of binomial by a binomial

• $:\implies \sf{ {x}^{2}(3y + 7) + 3y(3y + 7)}$

• $: \implies \sf{3 {x}^{2}y + 7 + 9 {y}^{2} + 21y}$

★ step 2

• putting the value of variables :

• $\sf : \implies {3 \times {1}^{2} \times 1 + 7 + 9 \times {1}^{2} + 21 \times 1}$

• $:\implies \sf{3 + 7 + 9 + 21}$

• $\ \sf{ \boxed{:\implies40}}$

★ step 3

• The final answer is :

$\: \: \: \: \: \: \: \: \: \huge \boxed {\boxed{ \boxed{\sf{:\red{\mapsto} \: 40}}}}$