Question

Compute the frequency of a wave if the maximum peak in an electromagnetic wave is separated by a distance of 8 inches. *​

Answer 1

As it is an electromagnetic wave, velocity(v) is equal to 3 X 10^8 ms-1.

v=3*10^8 ms-1

λ=8 inches or 20.32 cm or 0.2032 m

therefore, v=fλ

3*10^8=f X 0.2032

f=1476377952.76 Hz

or

f=1.47637795276*10^11 Hz

f=1.476 * 10^11 ms-1

Answer 2

Given:

The maximum peak in an electromagnetic wave is separated by a distance of 8 inches.

To Find:

The frequency of the wave.

Solution:

We know that the peak to peak distance in a wave is the wavelength.

So wavelength, λ= 8 inches = 0.2m

The relation between wavelength λ and  frequency ν of an electromagnetic wave is given as $c=$ λν

where $c$ is the speed of an electromagnetic wave in a vacuum.

   $3*10^8=0.2$ν

⇒ ν $=1.5*10^9Hz$

Hence, the frequency of the electromagnetic wave is equal to $1.5*10^9Hz$.